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Configuration = 27
cycles = (10 8 3 9 5)(7 4 1 6 2)

a = 2, b = 4, c = 6
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cycles = (10 8 5 9 3)(7 2)(6 1)(4)

a = 3, b = 5, c = 9
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cycles = (10 6 3)(9)(8)(7)(5 2)(4 1)

a = 2, b = 4, c = 5
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cycles = (10 6 4)(9)(8)(7)(5 1 2)(3)

a = 1, b = 2, c = 5
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cycles = (10 6 3)(9)(8)(7)(5)(4)(2)(1)